**Question 1: **Find the max, min, median and first quartile for the following set of data:
{4,5,7,8,3,9,10}.

** Solution: **

Given set of data is {4,5,7,8,3,9,10}
The order is {3,4,5,7,8,9,10}

Minimum = 3

Maximum = 10

No of data n = 7

The median is given by

Median = $\frac{n+1}{2}$ = $\frac{7+1}{2}$ = 4^{th} digit

$\therefore$ Median = 7

The first quartile Q_{1} = $\frac{n+1}{4}$ = $\frac{7+1}{4}$ = 2

The third quartile Q_{3} = $\frac{3(n+1)}{4}$ = 3 $\times$ 2 = 6

**Question 2: **Find the max, min, median and first quartile for the following set of data:
{10,5,3,8,11,10}.

** Solution: **

Given set of data is {10,5,3,8,11,10}.The order is {3,5,8,10,10,11}

Minimum = 3
and Maximum = 11

no of data given n = 6

The median is given by

Median = $\frac{n+1}{2}$ = $\frac{6+1}{2}$ = 3rd and 4th digit

$\therefore$ Median = $\frac{8 + 10}{2}$ = 9

The first quartile Q_{1} = $\frac{n+1}{4}$ = $\frac{6+1}{4}$ = 1.75

The third quartile Q_{3} = $\frac{3(n+1)}{4}$ =3 $\times$ 1.75 = 5.25.