**Question 1: **Find the area of the trapezoid having parallel sides as 4cm, 8cm and height is 10cm?

** Solution: **

Given: base b_{1} = 4 cm, base b_{2 }= 8 cm and height (h) = 10 cm

Area of trapezoid = $\frac{(b_1 + b_2)h}{2}$

Put the values in the formula to get

Area of trapezoid = $\frac{(4cm + 8 cm) \times 10 cm}{2}$

= $\frac{120}{2}$

Area of trapezoid = 60 cm^{2}.

**Question 2: **Find the area of the trapezoid having parallel sides as 5 cm, 8cm and height is 12 cm?

** Solution: **

Given: base b_{1 }= 5 cm, base b_{2} = 8 cm and height (h) = 12 cm.

Area of trapezoid = $\frac{(b_1 + b_2)h}{2}$

Put the values in the formula to get

Area of trapezoid = $\frac{(5 cm + 8 cm) \times 10 cm}{2}$

= $\frac{130}{2}$

Area of trapezoid = 65 cm^{2}.