**Question 1: **Solve given equation, 5x+2=3y+7

** Solution: **

The given equation is,

5x+2=3y+7

On rearranging we get,

5x+2-7=3y

5x-5=3y

5(x-1)=3y

y=$\frac{5(x-1)}{3}$

**Question 2: **Solve the given equation 3x+1=10y-7

** Solution: **

The given equation is,

3x+1=10y-7

On rearranging we get,

3x+1+7=10y

3x+8=10y

y=$\frac{1)}{10}$(3x+8)